(2x+3)(x^2+2x+5)=0

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Solution for (2x+3)(x^2+2x+5)=0 equation: 


Simplifying
(2x + 3)(x2 + 2x + 5) = 0

Reorder the terms:
(3 + 2x)(x2 + 2x + 5) = 0

Reorder the terms:
(3 + 2x)(5 + 2x + x2) = 0

Multiply (3 + 2x) * (5 + 2x + x2)
(3(5 + 2x + x2) + 2x * (5 + 2x + x2)) = 0
((5 * 3 + 2x * 3 + x2 * 3) + 2x * (5 + 2x + x2)) = 0
((15 + 6x + 3x2) + 2x * (5 + 2x + x2)) = 0
(15 + 6x + 3x2 + (5 * 2x + 2x * 2x + x2 * 2x)) = 0
(15 + 6x + 3x2 + (10x + 4x2 + 2x3)) = 0

Reorder the terms:
(15 + 6x + 10x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 6x + 10x = 16x
(15 + 16x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(15 + 16x + 7x2 + 2x3) = 0

Solving
15 + 16x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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